* 时间复杂度：O(len1 + len2)，空间复杂度：O(len2)（栈+Map的空间）
四步口诀：倒着来 → 弹 ≤ 当前的 → 栈顶即答案 → 当前入栈。
。关于这个话题，Line官方版本下载提供了深入分析
I thought it was time to try a similar experiment myself, one that would take one or two hours at max, and that was compatible with my Claude Code Max plan: I decided to write a Z80 emulator, and then a ZX Spectrum emulator (and even more, a CP/M emulator, see later) in a condition that I believe makes a more sense as “clean room” setup. The result can be found here: https://github.com/antirez/ZOT.
He says a lot of the accounts re-sharing his posts are likely doing it for views and clicks - and in an effort to monetise the content on other platforms like Facebook.
Keys that explicitly list the Generative Language API in their allowed services